AP Bio Ch. 16 Study Guide
Multiple Choice
Identify the
choice that best completes the statement or answers the question.
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1.
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Interactive question 16.1 A
How did they label phage
protein?
a. | they used radioactive hydrogen as a tag | b. | they used
radioactive oxygen as a tag | c. | they used radioactive carbon as a
tag | d. | they used radioactive sulfer as a tag | e. | they used radioactive nitrogen as a
tag | f. | they used radioactive phosphorous as a tag |
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2.
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Interactive question 16.1 B
How did they label phage
DNA?
a. | they used radioactive hydrogen as a tag | b. | they used
radioactive oxygen as a tag | c. | they used radioactive carbon as a
tag | d. | they used radioactive sulfer as a tag | e. | they used radioactive nitrogen as a
tag | f. | they used radioactive phosphorous as a tag |
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3.
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Interactive question 16.1 C
Where was the radioactivity found
in the samples with labeled phage protein?
a. | in the extracellular liquid | b. | in the bacterial cell
pellet |
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4.
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Interactive question 16.1 D
Where was the radioactivity found
in the samples with labeled phage DNA?
a. | in the extracellular liquid | b. | in the bacterial cell
pellet |
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5.
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Interactive question 16.1 E
What did Hershey and Chase conclude
from these results?
a. | that viral DNA is injected into the bacterial cells and serves as the heriditary
material for viruses | b. | that viral protein is injected into the
bacterial cells and serves as the heriditary material for viruses | c. | that viral RNA is
injected into the bacterial cells and serves as the heriditary material for
viruses | d. | all of these | e. | none of these |
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6.
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Interactive question 16.6
Why is DNA shortened during DNA
replication?
a. | DNA cannot grow on the 3’ end after the primer is removed because because no
3’ end is available for DNA polymerase | b. | DNA cannot grow on the 5’ end after the
primer is removed because because no 3’ end is available for DNA polymerase | c. | DNA cannot grow on
the 3’ end after the primer is removed because because no 5’ end is available for DNA
polymerase | d. | DNA cannot grow on the 5’ end after the primer is removed because because no
5’ end is available for DNA polymerase |
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Matching
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Interactive question 16.2 a. | nucleotide | h. | thymine
(pyramidine) | b. | 3’ end of chain | i. | cytosine | c. | 3.4 nm | j. | phosphate group | d. | 2
nm | k. | .34
nm | e. | adenine (purine) | l. | guanine | f. | deoxyribose | m. | sugar-phosphate backbone | g. | hydrogen
bonds | n. | 5’ end of
chain |
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7.
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A
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8.
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B
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9.
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C
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10.
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D
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11.
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E
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12.
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F
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13.
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G
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14.
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H
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15.
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I
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16.
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J
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17.
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K
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18.
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L
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19.
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M
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20.
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N
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Interactive question 16.3 a. | hybrid DNA only | d. | neither hybrid DNA
or light DNA | b. | light DNA only | e. | both hybrid DNA and light DNA | c. | heavy DNA only |
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21.
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first generation contained
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22.
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second generation contained
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23.
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parental generation contained
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Interactive question 16.4
Label the 5’ and 3’ ends
on the figure in 16.2
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24.
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underneath letter a.
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25.
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above letter i.
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26.
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below letter b.
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27.
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above letter h.
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Interactive question 16.5 a. | DNA pol III | h. | helicase | b. | primase | i. | Okazaki fragment | c. | DNA pol I (replacing
primer) | j. | DNA
ligase | d. | 5’ end of parental strand | k. | 3’ end | e. | lagging
strand | l. | leading
strand | f. | single-strand binding protein | m. | RNA primer | g. | DNA pol
III |
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28.
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A
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29.
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B
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30.
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C
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31.
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D
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32.
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E
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33.
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F
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34.
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G
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35.
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H
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36.
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I
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37.
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J
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38.
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K
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39.
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L
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40.
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M
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Interactive question 16.7
List the levels of packing in a
metaphase chromosome in order of increasing complexity. a. | 30-nm fiber | b. | coiling and folding
of looped domains | c. | nucleosomes and linker DNA | d. | looped
domains |
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41.
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lowest complexity
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42.
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more complex than #41
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43.
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more complex than #42
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44.
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highest complexity
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Structure Your Knowledge #2 a. | eases the twisting ahead of
replication fork by breaking, untwisting, and rejoining DNA | b. | replaces primer with
DNA | c. | unwinds the helix and seperates DNA strands | d. | joins the 3’
end of one fragment to the 5’ end of its neighbor | e. | synthesizes a primer
of 5-10 RNA bases to start the new strand | f. | support the seperated strands while replication
takes place | g. | joins the nucleotide to the 3’ end of the new
strand |
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45.
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helicase
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46.
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single-strand binding proteins
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47.
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topoisomerase
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48.
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primase
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49.
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DNA polymerase III
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50.
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DNA polymerase I
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51.
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ligase
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